Question

resolva em |R as equações 16 elevado a 5x-3 = 8 elevado a x+4

Answer 1

$16^{5x-3}=8^{x+4}\\\\(2^4)^{5x-3}=(2^3)^{x+4}\\\\2^{20x-12}=2^{3x+12}\\\\20x-12=3x+12\\\\20x-3x=12+12\\\\17x=24\\\\\boxed{x= \frac{24}{17}}\\\\\boxed{x=1,41}~~(aproximadamente)$

Answer 2

$16^{5x-3}=8^{x+4}$
-Primeiro temos que deixar as bases iguais.
$(2^4)^{5x-3}=(2^3)^{x+4}$
-Depois de igualarmos as bases trabalhamos somente com os expoentes.
$4(5x-3)=3(x+4)$
$20x-12=3x+12$
$20x-3x=12+12$
$17x=24$
[tex]\boxed{x= \frac{24}{17}}/tex]