• Matéria: Matemática
  • Autor: amandssramoss
  • Perguntado 7 anos atrás

Dados x= raiz quadrada de 1,777... e y=0,333... qual é o valor de (x-y) elevado a -2

Respostas

respondido por: CyberKirito
1

m=1,777...\times(10)\\10m=17,777....

\underline{\begin{cases}10m=17,\cancel{777...} \\m=1,\cancel{777...}\end{cases}}

9m=16\\m=\dfrac{16}{9}

x=\sqrt{1,777}\\x=\sqrt{\dfrac{16}{9}}=\dfrac{4}{3}

y=0,333\times(10)\\10y=3,333...

\underline{\begin{cases}10y=3,\cancel{333...} \\y=0,\cancel{333...}\end{cases}}

9y=3\\y=\dfrac{3\div3}{9\div3}\\y=\dfrac{1}{3}

x-y=\dfrac{4}{3}-\dfrac{1}{3}=\dfrac{3}{3}=1

\boxed{\boxed{\mathsf{{(x-y)}^{-2}={1}^{-2}=1}}}

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