• Matéria: Matemática
  • Autor: santosraiane325
  • Perguntado 7 anos atrás

Determine x sabendo que os angulos são complementares:

Anexos:

Respostas

respondido por: CyberKirito
1

a)

2x+x=90^{\circ}\\3x=90^{\circ}\\x=\dfrac{90^{\circ}}{3}

\boxed{\boxed{\mathsf{x=30^{\circ}}}}

b)

2x+4x+3x=90^{\circ}\\9x=90^{\circ}\\x=\dfrac{90^{\circ}}{9}

\boxed{\boxed{\mathsf{x=10^{\circ}}}}

c)

x+x+20^{\circ} =90^{\circ}\\2x=90^{\circ}-20^{\circ} \\2x=70^{\circ}\\x=\dfrac{70^{\circ}}{2}

\boxed{\boxed{\mathsf{x=35^{\circ}}}}

d)

2x+15^{\circ}+2x-25^{\circ} =90^{\circ}

4x=90^{\circ}+25^{\circ}-15^{\circ}\\4x=100^{\circ}\\x=\dfrac{100^{\circ}}{4}

\boxed{\boxed{\mathsf{x=25^{\circ} </p><p>}}}


santosraiane325: Muito obrigado rubens
CyberKirito: De nada ^^
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