Question

20+{6-[(2+11)]+5-(-5-6)+12}-32 soma augebica ​

Answer 1

   $20+[6-(2+11)+5-(-5-6)+12]-32=$

$=20+[6-(13)+5-(-11)+12]-32=$

$=20+(6-13+5+11+12)-32=$

$=20+(-7+5+11+12)-32=$

$=20+(-2+11+12)-32=$

$=20+(9+12)-32=$

$=20+21-32=$

$=41-32=$

$=9$