Question

como resolver 2+3 [x-(3x+1)]=5 [x-(2x-1)]
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Answer 1

Resposta:

2+3 [x-(3x+1)]=5 [x-(2x-1)]

2+3[x-3x-1]=5[x-2x+1]

2+3[-2x-1]=5[-x+1]

2-6x-3=-5x-5

2-3+5= -5x+6x

x= 4