Question

2x^2 - 8x + 8 =0 ..por favor me ajudem ..

Answer 1

$2x^2 - 8x + 8 =0\\\\ a=2;b=-8;c=8\\\\\\ \Delta=b^2-4ac\to \Delta=(-8)^2-4*2*8\to \Delta=64-64\to \Delta=0\\\\ x'=x''\\\\ x= \frac{-b\pm \sqrt{\Delta} }{2a} \to x= \frac{-(-8)\pm \sqrt{0} }{2*2} \to x= \frac{8\pm 0 }{4} \to \\\\\\ x'=x''= \frac{8 }{4} \to x'=x''=2\\\\\\\\ S=\left \{2 \left \}$