Question

$4 \sqrt{63} - \sqrt{7}$
$2 \sqrt{27} - 5 \sqrt{12}$
$\frac{ \sqrt[3]{16} + \sqrt[3]{54} }{ \sqrt[3]{125} }$
$\sqrt[3]{2} \sqrt{ {2}^{4} }$



reduza a um único radical e em seguida simplifique se possível ​

Answer 1

Resposta:

a)11$\sqrt{7}$

b)-4$\sqrt{3}$

c)$\sqrt[3]{2}$

d)4$\sqrt[3]{2}$

Explicação passo-a-passo:

a)4$\sqrt{63}$-$\sqrt{7}$=4$\sqrt{7*9}$-$\sqrt{7}$=4$\sqrt{3*3*7}$-$\sqrt{7}$=12$\sqrt{7}$-$\sqrt{7}$=11$\sqrt{7}$

b)2$\sqrt{27}$-5$\sqrt{12}$=2$\sqrt{3*3*3}$-5$\sqrt{3*2*2}$=6$\sqrt{3}$-10$\sqrt{3}$=-4$\sqrt{3}$

c)($\sqrt[3]{16}$+$\sqrt[3]{54}$)/$\sqrt[3]{125}$=($\sqrt[3]{2*2*2*2}$+$\sqrt[3]{2*3*3*3}$)/$\sqrt[3]{5*5*5}$=(2$\sqrt[3]{2}$+3$\sqrt[3]{2}$)/5=5$\sqrt[3]{2}$/5=$\sqrt[3]{2}$

d)$\sqrt[3]{2}$*$\sqrt{2^{4} }$=$\sqrt[3]{2}$*$2^{4/2}$=$\sqrt[3]{2}$*$2^{2}$=4$\sqrt[3]{2}$