Question

x2 - 2x - 1 x= -1 na formula de Bhaskara
2

Answer 1

Resolvendo :

$x^2-2x-1x=-1 \\ x^2-3x+1=0 \\ delta=-3^2-4.1.1 \\ delta=9-4 \\ delta=5 \\ \\ \frac{-(-3)+- \sqrt{5} }{2*1} = \frac{3+- \sqrt{5} }{2} \\ \\ x'= \frac{3+ \sqrt{5} }{2} \\ x''= \frac{3- \sqrt{5} }{2}$