Question

O valor da Integral Indefinida...

Answer 1

Resposta:

∫ (8x⁴ -9x³+6x²-2x+1)/x² - 2*∛x  dx

=∫ (8x² -9x+6-2/x+1/x² - 2*x^(1/3)  dx

=8x³/3 -9x/2 +6x-2ln|x| -2*x^(1/3+1) /(1/3+1)  + constante

=8x³/3 -9x/2 +6x-2ln|x| -2*x^(4/3) /(4/3)  + constante

=8x³/3 -9x/2 +6x-2ln|x| -6*x^(4/3) /(4)  + constante

=8x³/3 -9x/2 +6x-2ln|x| -3*x^(4/3) /2  + constante

Answer 2

Resposta:

8x³/3 -9x/2 +6x-2ln|x| -3*x^(4/3) /2  + constante

Explicação passo-a-passo: