Question

Dadas as funções f(x) = 3x² – 27, g(x) = 2x² – 4x e h(x) = x² + 2x + 1.

Qual o valor de f(3) + g(2) + h(–1)?



Escolha uma:
a. 0
b. 2
c. 4
d. 3
e. 1

Answer 1

f(x) = 3x² – 27

f(3) = 3x² – 27

f(3) = 3*3² – 27

f(3) = 3 * 9 - 27 = 0

g(x) = 2x² – 4x

g(2) = 2*2² – 4*2

g(2) = 2*4 – 4*2 = 0

h(x) = x² + 2x + 1

h(–1) = (–1)² + 2(–1) + 1

h(–1) = 1 - 2 + 1 = 0

f(3) + g(2) + h(–1) = 0