Question

01_Qual é o valor de X,considerando que os ângulos internos de um triângulo medem 5x,11 e 2x?

02_Determine o valor de x no triângulo a seguir.

03_Determine o valor dos ângulos no triângulo abaixo

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Answer 1

1)

$\mathsf{5x+11^{\circ}+2x=180^{\circ}}\\\mathsf{7x=180^{\circ}-11^{\circ}}\\\mathsf{7x=169^{\circ}}\\\mathsf{x\approx24^{\circ}8'34\\"}$

2)

$\mathsf{\cancelx+40^{\circ}-\cancelx+2x+10^{\circ}=180^{\circ}}\\\mathsf{2x=180^{\circ}-10^{\circ}-40^{\circ}}\\\mathsf{2x=130^{\circ}}\\\mathsf{x=\dfrac{130^{\circ}}{2}}$

$\boxed{\boxed{\mathsf{x=65^{\circ}}}}$

3) teorema do ângulo externo de um triângulo

$\mathsf{Em\,todo\,tri\^{a}ngulo\,o\,\^{a}ngulo\,externo\,\'e\,igual\,a\,soma\,dos\,\^{a}ngulos\,internos\,n\tilde{a}o\,adjacentes}$

portanto

$\boxed{\boxed{\mathsf{x=60^{\circ}+40^{\circ}=100^{\circ}}}}$