Question

O valor de y=cos150°+sen330°-tg150°-cos270° é?​

Answer 1

Resposta:

$y = - \frac{ \sqrt{3} }{2} + ( - \frac{1}{2} ) - ( - \frac{ \sqrt{3} }{3} ) - 0 \\ y = - \frac{ \sqrt{3} }{2} - \frac{1}{2} + \frac{ \sqrt{3} }{3} \\ y = \frac{ - 3 \sqrt{3} - 3 + 2 \sqrt{3} }{6} \\ \boxed{y = \frac{ - \sqrt{3} - 3}{6}}$