• Matéria: Matemática
  • Autor: rafaelthome13rafael
  • Perguntado 9 anos atrás

me ajudeem...6x-5x²+2=-10+2x

Respostas

respondido por: aluno029
0
6x-5x²+2=-10+2x
6x-5x²+2+10 -2x=0
-5x²+4x+12=0 · (-1)
5x²-4x-12=0
 a=5 b=-4 c=-12
Δ=b²-4ac
Δ=(-4)²-4·5·(-12)
Δ=16+240
Δ=256

x=-b+-√Δ/2a
x=-(-4)+-√256/2·5
x=4 +-16/10
x'=-12
      10
x"=2
soluçao:{-12 , 2}
              10
respondido por: LuanaSC8
0
6x-5 x^{2} +2=-10+2x\to\\\\ 6x-5 x^{2} +2+10-2x=0\to \\\\ -5 x^{2} +4x+12=0\\\\ a=-5;b=4;c=12\\\\\\ \Delta=b^2-4ac\to \Delta=4^2-4*(-5)*12\to \Delta=16+240\to \Delta=256\\\\ \Delta\ \textgreater \ 0\to x' \neq x''


x= \frac{-b\pm \sqrt{\Delta} }{2a} \to x= \frac{-4\pm \sqrt{256} }{2*(-5)} \to  \to x= \frac{-4\pm 16 }{-10} \to \\\\ \\x'= \frac{-4+16 }{-10} \to x'= \frac{12 }{-10} \to x'=- \frac{6}{5} \\\\\\ x''= \frac{-4-16 }{-10} \to x''= \frac{-20 }{-10} \to x''=2\\\\\\\\ S=\left \{ - \frac{6}{5}; 2\left \}
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