Question

Resolva pela forma de bhaskara
a) 2x²-19x-10=0

Answer 1

2x^2-19x-10=0
delta=b^2-4ac
delta=(-19)^2-4.2.(-10)
delta=361+80
delta=441
x=-b-/+ raiz de delta/2a
x=-(-19)-21/2.2
x=19-21/4
x=-2/4 (:2)
x=-1/2
x=-(-19)+21/2.2
x=19+21/4
x=40/4
x=10