Question

Qual a quantidade de substância (n) equivalente a 1,25 g de diclorometano?

Answer 1

$\mathsf{m_{CH_{2}Cl_{2}}=12+2.1+2.35,5=85g/mol}$

$\mathsf{1\,mol\,de\,CH_{2}Cl_{2}\rightarrow\,85g}\\\mathsf{x\,mols,de\,CH_{2}Cl_{2}\rightarrow\,1,25g}$

$\mathsf{85x=1,25}\\\mathsf{x=\dfrac{1,25}{85}}$

$\boxed{\boxed{\mathsf{x\approx0,01\,mols\,de\,CH_{2}Cl_{2}}}}$