Question

determine o valor de "b" no sistema linear: { a+b-3c+d=1
-b+7c-d=2
+10c-d=-3
3d=39
a. 13
b. -8
C. 8
d. 1
e.-1

Answer 1

$\large\mathsf{\begin{cases}a+b-3c+d=1\\-b+7c-d=2\\10c-d=-3\\3d=39\end{cases}}$

$\mathsf{3d=39\rightarrow\,d=\dfrac{39}{3}=13}$

$\mathsf{10c-13=-3}\\\mathsf{10c=13-3}\\\mathsf{10c=10\rightarrow\,c=\dfrac{10}{10}=1}$

$\mathsf{-b+7.1-13=2}\\\boxed{\boxed{\mathsf{b=7-13-2=-8}}}$

Answer 2

Resposta:

letra b -8

Explicação passo a passo:

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