Question

Alguém me ajuda por favor?


x²+6x=0

Answer 1

Resposta:

x=-b²±√∆/2a. ∆=b²-4ac

X=-6±√6²-4×1×0/2×1

X=-6±√36/2

X=-6±6/2

x¹=-6-6/2, x¹=-6

x²=-6+6/2, x¹=0

Answer 2

x•(x+6 )

x=0 x+6=0
x=-6

S={0,-6}