Question

Se x é log 2(base) 16 - log4(base) 32, então o X vale?

Answer 1

x = log(2)16 - log(4)32
x = log(2)2^4 - log(2²)2^5
x = 4log(2)2 - 5.1/2.log(2)2
x = 4 . 1 - 5/2 . 1
x = 4 - 5/2
x = 8/2 - 5/2
x = 3/2