Question

1- Calcule as somas Algébricas, cancelando os números opostos , quando possivel:



a) 40 – 3 + 15 + 40 – 10 =

b) – 15 – 20 – 8 – 5 =

c) 3 + 2 + 10 + 1 =

d) – 6 + 4 + 6 =

e) – 11 + 30 – 9=

f) 5 – 4 + 2 – 4 + 1 – 3 =

g) – 9 – 4 + 8 + 6 + 14 – 10 =

h) -3 – 4 – 5 + 3 + 6 =

i) 21 + 45 + 36 – 45 – 21 = 36

j) 9 + 15 – 5 + 35 – 20 =

k) -6 – 5 – 4 – 3 + 4 + 6 + 5 + 3=

l) 168 – 432 + 365 =

m) – 999 + 333 – 1 + 666=

n) – 7 – 7 + 17 – 3 =

o) – 20 + 20 – 4 + 40 – 50 =

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Answer 1

Resposta:

Explicação passo-a-passo:

A)95-13=82

B)-48

C)16

D)+10-6=4

E)-20+30=10

F)-11+8=3

G)13-23=-10

H)-12+9=-3

I)92-66=26

J)59-25=34

K)-18+18=0

L)533-432=101

M)999-1000=-1

N)-17+17=0

O)-74+60=-14