Question

$3 {y}^{2} - 14y + 8 = 0$
​

Answer 1

Delta =b^2 -4ac
Delta =14^2-4.3.8
Delta =196-96
Delta=100

Logo

-b+ou- raiz de delta/2a =
-(-14)-10/6=
4/6

-b+raiz de delta/2a=
-(-14)+10/6=
8