Question

calcule a distancia emtre os pontos dados

p(3,-3) e q(-3,3)

Answer 1

$d_{ab} = \sqrt{(xb-xa)^2 + ({yb-ya})^2} \\ \\ d_{ab} = \sqrt{(-3-3)^2 + ({3+3})^2} \\ \\ d_{ab} = \sqrt{-6^2 + 6^2} \\ \\ d_{ab} = \sqrt{36+36} \\ \\ d_{ab} = \sqrt{72} \\ \\ d_{ab} \approx 8.5$