Question

3x elevado a 2+10x-8=0
resposta completa dou 55 pontos (urgente)

Answer 1

$3 x^{2} +10x-8=0\\\\ a=3;b=10;c=-8\\\\\\ \Delta=b^2-4ac\to \Delta=10^2-4*3*(-8)\to \Delta=100+96\to \Delta=196\\\\ x' \neq x''\\\\\\ x= \frac{-b\pm \sqrt{\Delta} }{2a} \to x= \frac{-10\pm \sqrt{196} }{2*3} \to x= \frac{-10\pm 14 }{6} \to \\\\\\ x'= \frac{-10+ 14 }{6} \to x'= \frac{4 }{6} \to x'= \frac{2}{3} \\\\\\ x''= \frac{-10- 14 }{6} \to x''= \frac{-24 }{6} \to x''=-4\\\\\\\\ S= \left \{-4; \frac{2}{3} \left \}$



Soma das raízes:

$-4+ \frac{2}{3} \to mmc=3\to \frac{-12+2}{3} \to \frac{-10}{3}$


Produto das raízes:

$-4* \frac{2}{3} \to \frac{-8}{3}$