Question

Calcule o ponto médio das coordenadas de A(7/2, 4) e B( 3/2, 8) *

Answer 1

$\textsf{O ponto medio dos pontos }\mathsf{P(x_1,y_1) \ e \ Q(x_2,y_2) \ \'e \ R(\frac{x_1 +x_2}{2}, \frac{y_1+y_2}{2}).}$

$\textsf{Assim, o ponto medio de A e B \'e:}\\\\\mathsf{M =\bigg(\dfrac{\frac{7}{2} + \frac{3}{2}}{2}, \dfrac{2 + 8}{2}\bigg) = \bigg(\dfrac{\frac{10}{2}}{2}, \dfrac{10}{2}\bigg) = \bigg(\dfrac{10}{4}, \dfrac{10}{2}\bigg)}$