Question

Dado log 2=0,30 log 3= 0,47 e log 5=0,70 calcule log raiz de 10​

Answer 1

Resposta:

Explicação passo-a-passo:

log 2 = 0,30; log 3 =0,48 e o log 5= 0,70, calcule:

a) log 20 = log(2².5) = log2² + log5 = 2log2 + log5

 

2(0,30)+0,70==>0,60+0,70 ==> 1,30

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b) log 0,0002 = log(2.10^-4) = log 2 + log10^-4 = log2 - 4log10

0,30 - 4.1 ==> - 3,70

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c) log 0,3 = log(3.10^-1) = log3 - 1. log10 = 0,48 - 1 ==> - 0,52 

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d) log 18 = log (2.3²) = log2 + log3² = log2 + 2log3 

 

0,30+ 2.(0,48) ==> 0,30 + 0,96==> 1,26

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e) log 45 = log (3².5) = log3² + log5 = 2log3 + log5

2(0,48) + 0,70 ==> 0,96+0,70 ==> 1,66

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f) log 250 = log(2 . 5³) = log2 + log5³ = log2 + 3log5

0,30+ 3(0,70) = 0,30 + 2,10 ==> 2,40

Answer 2

log ²√10 = log 10 / 2 = 1 / 2 <======©