Question

Interpole sete meios aritméticos entre -2 e 22

Answer 1

n = 2 (termos já existentes) + 7 = 9 termos

$a_{1}=-2$
$a_{9}=22$

$a_{n}=a_{1}+(n-1)r$
$a_{9}=a_{1}+(9-1)r$
$a_{9}=a_{1}+8r$
$22=-2+8r$
$22+2=8r$
$24=8r$
$24/8=r$
$r=3$
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$a_{2}=a_{1}+r = -2+3=1$
$a_{3}=a_{2}+r=1+3=4$
$a_{4}=a_{3}+r=4+3=7$
$a_{5}=a_{4}+r=7+3=10$
$a_{6}=a_{5}+r=10+3=13$
$a_{7}=a_{6}+r=13+3=16$
$a_{8}=a_{7}+r=16+3=19$