Question

2) Aplicando a definição de potência, calcule o valor de:

Answer 1

$\large\boxed{\begin{array}{l}\sf\bigg(-\dfrac{1}{2}\bigg)^5=\bigg(-\dfrac{1}{2}\bigg)\cdot\bigg(-\dfrac{1}{2}\bigg)\cdot\bigg(-\dfrac{1}{2}\bigg)\cdot\bigg(-\dfrac{1}{2}\bigg)\cdot\bigg(-\dfrac{1}{2}\bigg)\\\\\sf \bigg(-\dfrac{1}{2}\bigg)^5=-\dfrac{1}{32}~\blue{\checkmark}\end{array}}$