Question

1- calcule
a) (x/4 + 1)²
b) (x/4 - 1)²
c) (3ab - b²/3)²

Answer 1

a) (x/4 + 1)²

$\frac{x {}^{2} }{16} + \frac{x}{2} + 1$

b) (x/4 - 1)²

$\frac{x {}^{2} }{16} - \frac{x}{2} - 1$

c) (3ab - b²/3)²

$9a {}^{2} b {}^{2} - \frac{2ab {3}^{} }{3} + \frac{b {4}^{} }{81}$

Bons estudos ♡