Question

Resolva a equação: (y+3)²-(y-2)²-17=0

Answer 1

$\mathtt{{(y+3)}^{2}-{(y-2)}^{2}-17=0}$

$\mathtt{{y}^{2}+6y+9-({y}^{2}-4y+4)-17=0}$

$\mathtt{\cancel{{y}^{2}} +6y+9-\cancel{{y}^{2}} +4y-4-17=0}$

$\mathtt{6y+4y=17+4-9}$

$\mathtt{10y=12}\\\mathtt{y=\dfrac{12\div2}{10\div2}}$

$\huge\boxed{\boxed{\mathtt{y=\dfrac{6}{5}}}}$