Question

uma escala possui os valores de 59°x e 189°x para os pontos fixos

Construa a equação termométrica dessa escala e relacione com 300k​

Answer 1

$\mathtt{\dfrac{t_{X}-59^{\circ}}{189^{\circ}-59^{\circ} }=\dfrac{t_{K}-273}{373-273}}$

$\mathtt{\dfrac{t_{X}-59^{\circ}}{130\div10}=\dfrac{t {K}-273}{100\div10}}$

$\mathtt{\dfrac{t_{X}-59^{\circ}}{13}=\dfrac{t {K}-273}{10}}$

$\mathtt{\dfrac{t_{X}-59^{\circ}}{13}=\dfrac{300-273}{10}}$

$\mathtt{\dfrac{t_{X}-59^{\circ}}{13}\dfrac{27}{10}}$

$\mathtt{10t_{x}-590^{\circ}=27.13}$

$\mathtt{10t_{x}=590^{\circ}+351^{\circ}}$

$\mathtt{10t_{X}=941}\\\mathtt{t_{X}=\dfrac{941}{10}}$

$\boxed{\boxed{\mathtt{t_{X}=94,1^{\circ}X}}}$