• Matéria: Física
  • Autor: keyllaalmeida1234
  • Perguntado 6 anos atrás

log(2x - 1) = 1/2 me ajudaaaaaaaaaaaaa​

Respostas

respondido por: CyberKirito
1

\mathtt{log~2x-1=\dfrac{1}{2}}\\\mathtt{2x-1={10}^{\frac{1}{2}}}\\\mathtt{2x-1=\sqrt{10}}

\mathtt{2x=\sqrt{10}+1}

\huge\boxed{\boxed{\mathtt{x=\dfrac{\sqrt{10}+1}{2}}}}


keyllaalmeida1234: obrigada
CyberKirito: De nada
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