Question

log
$3 \sqrt[3]{3}$
na base 27​

Answer 1

Explicação passo-a-passo:

$\log_{27}3\sqrt[3]{3} =x\\ \\ 27^x=3\sqrt[3]{3} \\ \\ (3^3)^x=3.3^{1\over3}\\ \\ 3^{3x}=3^{3+1\over3}\\ \\ 3^{3x}=3^{4\over3}\\ \\ 3x={4\over3}\\ \\ 9x=4\\ \\ x={4\over9}\\ \\ logo\\ \\\fbox{ \log_{27}3\sqrt[3]{3} ={4\over9} }$