Question

sendo logx a=8, logx b=2 e log x c=1, calcular; a)logx ³√a.b/c

Answer 1

$log_{x} \sqrt[3]{a} . \frac{b}{c} \\ log _{x} a^{ \frac{1}{3}}+log_{x}b-log_{x}a \\ \frac{1}{3} .log_{x}a + log_{x}b - log_{x}c \\ \frac{1}{3} .8 + 2 - 1 \\ \frac{8}{3} + 1 \\ \frac{8+3}{3} \\ \frac{11}{3}$

Espero ter ajudado.