Question

$( {2x}^{2} ) {}^{2}$

$( - {3a}^{2} ) {}^{3}$

$( + {2x}^{2} y) {}^{3}$

$( - {xy}^{2})4$

$( - 5x4y) {}^{1}$

$( \frac{1}{2} a) {}^{2}$

​

Answer 1

Está aqui se tiver dúvidas eu explico

Answer 2

Resposta:

$(2x^{2}) ^{2} = 4x^{2*2} = 4x^{4}$

$(-3a^{2} )^{3} = -27a^{2*3} = -27a^{6}$

$(2x^{2} y)^{3} = 8x^{2*3} y^{3} = 8x^{6} y^{3}$

$(-xy^2)^4= x^4y^{2*4}= x^4y^8$

$(-5x4y)^1=-5x4y$

$(\frac{1}{2} a)^2=\frac{1}{4} a^2$