Question

X2 + 2X + 0 = 0

X2 - 3X + 0= 0

Answer 1

$a) \: Δ = {2}^{2} - 4.1.0 \\ Δ = 4 - 0 = 4$

$\frac{ - 2 + 2}{2} = \frac{0}{2} = 0$

$\frac{ - 2 - 2}{2} = \frac{ - 4}{2} = - 2$

S = {0, -2}

$b) \: Δ = { - 3 }^{2} - 4.1.0 \\ Δ = 9 - 0 = 9$

$\frac{3 + 3}{2} = \frac{6}{2} = 3$

$\frac{3 - 3}{2} = \frac{0}{2} = 0$

S = {3, 0}