Question

me ajudem por favor
a) (√2) ^6+ (2√3)⁴ + (-3√7)2 =
b) (³√√64)²=​

Answer 1

Resposta:

$b)\\\\ Resolve-a-raiz-de-dentro-e-depois-a-de-fora...\\\\(\sqrt[3]{\sqrt{64}})^{2} = (\sqrt[3]{8}})^{2} = (2)^2 = 4$

Explicação passo-a-passo:

$a)\\\\(\sqrt{2}) ^{6} +(2\sqrt{3} )^4+(-3\sqrt{7} )^2\\2^\frac{1}{2}^{.6} + (3.2^\frac{1}{2}^{.4} ) +(- 7.3^\frac{1}{2}^{.2})\\ 2^\frac{12}{2} + 6^\frac{8}{2} - 21^\frac{4}{2} \\2^6+6^4-(21)^2\\64+1296- 441\\1360-441\\919$