Question

x²-5x+6=0 determine a equção.

Answer 1

$x^{2} -5x+6=0 \Delta= b^{2} -4.a.c \Delta -5^{2} -4.1.6 \Delta=25-24=1 x1=-+(-5) \sqrt{1} /2=5-1/2=4/2=2 x2=-+(-5) \sqrt{1} /2=5+1/2=6/2=3$


S=\{2,3}\

Answer 2

x²-5x+6=0
a=1 b=-5 c=6
Resolvendo por Bhaskara, temos:
Δ=b²-4ac
Δ= (-5)²-4·1·6
Δ= 25-25
Δ= 1

Encontrando as raízes:

x= -b + - √Δ/2a
x= - (-5) + - √1/2·1
x= 5 + - 1 /2

x'= 6/2 
x'= 3

x''= 4/2
x''= 2

S:[ 2,3]