Question

∫2^0∫1^0(2x+y)²dx dy

Answer 1

Resposta:

Se for 0 a 2∫ 0 a 1 ∫(2x+y)²dx dy

0 a 2∫ 0 a 1 ∫4x²+4xy+y²dx dy

0 a 2∫ 0 a 1 [4x³/3+4x²y/2+xy²] dy

0 a 2∫  [4/3+2y+y²] dy

0 a 2 [ 4y/3+y²+y³/3]

=8/3+4+8/3

=16/3+4

=(16+12)/3  = 28/3 unidade de área