Question

a) 2x² - 128 = 0 ? Me ajudem


a) x ² + 8x + 12 = 0

Answer 1

a) 2x² - 128 = 0
2x^2 = 128
x^2 = 128/2
x^2 = 64
x = +- √ 64
x = +- 8

S = { 8 ; - 8 }

a) x ² + 8x + 12 = 0
x = - 8 +- 4/2
x' = - 2
x" = - 6

S = { - 2 ; - 6 }

Answer 2

a) 2x^2-128=0
2x^2=0+128
2x^2=128
x^2=128/2
x^2=64
x= raiz de 64
x=-/+8
b) x^2+8x+12=0
delta=b^2-4ac
delta=8^2-4.1.12
delta=64-48
delta=16
x=-b-/+ raiz de delta/2a
x=-8-4/2.1
x=-12/2
x=-6
x=-8+4/2.1
x=-4/2
x=-2