Question

2ײ+x-3=0
equação do 2 grau ​

Answer 1

Resposta:

a = 2 || b = 1 || c = -3

Bhaskara

$x = \frac{-b+- \sqrt{b^2 - 4.a.c} }{2.a}$

$x = \frac{-1+- \sqrt{1^2 - 4.2.(-3)} }{2.2}$

$x = \frac{-1+- \sqrt{1 + 24} }{4}$

$x' = \frac{-1+ \sqrt{25} }{4} = \frac{-1 + 5}{4} = \frac{4}{4} = 1 \\\\x'' = x = \frac{-1- \sqrt{25} }{4} = \frac{-1-5}{4}=\frac{-6}{4}= -\frac{3}{2}$

Portanto, a resposta é as raízes:

x' = 1

x'' = - 3/2