Question

trigonometria, pode me ajudar nesta?​

Answer 1

${a}^{2} = ( \sqrt{3)^{2} } + {4}^{2} - 2.4 \sqrt{3} . \cos(30)$

${a}^{2} = 3 + 16 - 8 \sqrt{3.} \frac{ \sqrt{3} }{2}$

${a}^{2} = 19 - \frac{8.3}{2}$

${a}^{2} = 19 - 12$

${a}^{2} = 7$

$a = \sqrt{7}$