Question

Dadas as matrizes

A = [ 1 3 4 5

√3 1/5 0 1

2 6 2/3 −2]

B= [3 2 1

4 5 8]

determine o valor do elemento cuja posição é:

(Matriz A)

a) a12 = b) a23 = c) a32 = d) a34 = e) a41 =


(Matriz B)

f) b21 = g) b23 = h) b32 = i) b11 = j) b13 =

Answer 1

$\mathsf{A=\begin{bmatrix}1&3&4&5\\\sqrt{3}&\dfrac{1}{5}&0&1\\2&6&\dfrac{2}{3}&-2\end{bmatrix}}\\\mathsf{B=\begin{bmatrix}3&2&1\\4&5&8\end{bmatrix}}$

(Matriz A)

$a)\mathsf{a_{12}=3}\\b)\mathsf{a_{23}=0}\\c)\mathsf{a_{32}=2}\\d)\mathsf{a_{34}=-2}\\e)n\tilde{a}o~~existe$

(Matriz B)

$f)\mathsf{b_{21}=4}\\g)\mathsf{b_{23}=8}\\h)n\tilde{a}o~existe\\i)\mathsf{b_{11}=3}\\j)\mathsf{b_{13}=1}$