Question

determine no caderno

A.
$\sqrt[5]{ - 243}$
B.
$\sqrt{0.01}$
C.
$\sqrt[3]{ \frac{1}{8} }$
D.
$\sqrt[5]{ \frac{1}{32} }$
​

Answer 1

A.

$\sqrt[5]{-243} = 3\sqrt[5]{-1}$

B.

$\sqrt{0,01}= 0,1$

C.

$\sqrt[3]{\frac{1}{8} } = \frac{\sqrt[3]{1} }{\sqrt[3]{8} } = \frac{1}{2}$

D.

$\sqrt[5]{\frac{1}{32} }= \frac{\sqrt[5]{1} }{\sqrt[5]{32} }= \frac{1}{2}$

Answer 2

Explicação passo-a-passo:

$A)\\ \sqrt[5]{-243} =\sqrt[5]{-3^5} =\sqrt[5]{-1} .\sqrt[5]{3^5} =-1(3)=-3\\ \\ B)\\ \sqrt{0,01} =\sqrt{{1\over100}} ={1\over10}=0,1\\ \\ C)\\ \\ \sqrt[3]{{1\over8}} =\sqrt[3]{({1\over2})^3} ={1\over2}\\ \\ D)\\ \sqrt[5]{1\over32}} =\sqrt[5]{({1\over2})^5} ={1\over2}$