Question

4) Simplifique os radicais e efetue as operações:
a)3√5+√20=
b) 2√2 + √8 =
c)√12-6√3=
d) √20 - √45 =
e) √5 . √7 =
f) 4√2 . 5√3 =
g) ⁴√10 : ⁴√2 =
h) 15√6 : 3√2 =

Answer 1

Resposta:

a)3√5+√20=  3$\sqrt{5}$ + $\sqrt{4.5}$ = 3$\sqrt{5}$ + 2$\sqrt{5}$  = 5$\sqrt{5}$

b) 2√2 + √8 = 2$\sqrt{2}$ + $\sqrt{2.4}$ = 2$\sqrt{2}$  + 2$\sqrt{2}$  = 4$\sqrt{2}$

c)√12-6√3= $\sqrt{4.3}$ - 6$\sqrt{3}$ = 2$\sqrt{3}$ - 6$\sqrt{3}$ = -4$\sqrt{3}$

d) √20 - √45 = $\sqrt{4.5}$ - $\sqrt{9.5}$ = 2$\sqrt{5}$ - 3 $\sqrt{5}$ = -1 $\sqrt{5}$

e) √5 . √7 = $\sqrt{5.7}$ = $\sqrt{35}$

f) 4√2 . 5√3 = 20$\sqrt{6}$

g) ⁴√10 : ⁴√2 = $\sqrt[4]{10/2}$ =  $\sqrt[4]{5}$

h) 15√6 : 3√2 = $\frac{5\sqrt{6} }{\sqrt{2}}$ ---- Racionalize:  $\frac{5\sqrt{6} }{\sqrt{2}}$ .$\frac{\sqrt{2}}{\sqrt{2}}$ = $\frac{5\sqrt{12} }{2}$ = $\frac{5\sqrt{3.4} }{2}$ = $\frac{5.2.\sqrt{3} }{2}$ = $5\sqrt{3}$