Question

16x elevado a 2-24x+5=0

Answer 1

Explicação passo-a-passo:

16x² - 24x + 5 =0

coeficientes

a=16

b=-24

c=5

Δ=b² -4ac

Δ=(-24)² -4(16)(5)

Δ=576-320

Δ= 256

$x={-b\pm\sqrt{\Delta} \over2a}={-(-24)\pm\sqrt{256} \over2.(16)}={24\pm16\over32}\\ \\ x'={24+16\over32}={40\over32}={5\over4}\\ \\ x"={24-16\over32}={8\over32}={1\over4}\\ \\ S=\{{1\over4},{5\over4}\}$