Question

determine a matriz  A= (aij)₃×₃tal q aij=i-j

Answer 1

$a_{ij}$

$\left[\begin{array}{ccc} a_{11} &a_{12}&a_{13}\\a_{21}&a_{22}&a_{23}\\a_{31}&a_{32}&a_{33}\end{array}\right]$


$a_{ij} = i - j$

$\left[\begin{array}{ccc}(1-1)&(1 - 2) & (1 - 3)\\(2 -1) &(2 - 2)&(2 - 3)\\(3 -1 )&(3 - 2)&( 3 -3)\end{array}\right]$

A = $\left[\begin{array}{ccc}0&- 1&- 2\\1& 0 &-1 \\2&1&0\end{array}\right]$


Bons Estudos!

Answer 2

 a11 a12 a13      0  - 1  - 2
 a21 a22 a23      1    0   - 1
 a31 a32 a33      2    1     0


a11 = 1-1=0
a12 = 1-2= - 1
a13 = 1-3= -2
a21 = 2-1=1
a22 = 2-2=0
a23 = 2-3=-1
a31 = 3-1=2
a32 =3-2=1
a33= 3-3=0