Question

Qual a resolução dessa equação do 2º grau????

Answer 1

Resposta:

Explicação passo-a-passo:

m.m.c ⇒ 4

8x² - 6x + 1 = 0

x = _6±√[(-6)² - 4(8)(1)]_

                 2(8)

x = _6±√(36- 32)_

              16

x = _6±2_

         16

x' = (6 + 2)/16 ⇒ x' = 1/2

x'' = (6 - 2)/16  ⇒ x'' = 1/4

Answer 2

Resposta:

Explicação passo-a-passo:

$a=2\\\\b=-\dfrac{3}{2}\\\\c=\dfrac{1}{4}$

Substituindo na fórmula

$x=\dfrac{-(-\dfrac{3}{2})\pm\sqrt{(-\dfrac{3}{2})^{2}-4.2.\dfrac{1}{4}}}{2.2}\\\\\\x=\dfrac{\dfrac{3}{2}\pm\sqrt{\dfrac{9}{4}-\dfrac{8}{4}}}{4}\\\\\\x=\dfrac{\dfrac{3}{2}\pm\sqrt{\dfrac{1}{4}}}{4}\\\\\\x=\dfrac{\dfrac{3}{2}\pm{\dfrac{1}{2}}}{4}=\dfrac{\dfrac{3\pm1}{2}}{4}\\\\\\x=\dfrac{3\pm1}{2}.\dfrac{1}{4}=\dfrac{3\pm1}{8}\\\\\\x'=\dfrac{3+1}{8}=\dfrac{4}{8}=\dfrac{1}{2}\\\\\\x''=\dfrac{3-1}{8}=\dfrac{2}{8}=\dfrac{1}{2}$

correção : $x''=\dfrac{1}{4}$