Question

Quais as raízes da equação x² - 10x + 25 = 0. Cálculo bhaskara

Answer 1

x² - 10x + 25 = 0

a = 1    b = -10    c = 25

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a} =\frac{-(-10)\pm\sqrt{(-10)^2-4\cdot1\cdot25} }{2\cdot1} =\frac{10\pm\sqrt{100-100}}{2} =\frac{10\pm\sqrt{0}}{2}=\frac{10\pm0}{2} \\\\x'=\frac{10+0}{2}=\frac{10}{2}=5\\\\x''=\frac{10-0 }{2}=\frac{10}{2}=5$

S = {5}