Question

determine as raízes da questão x²+5x+6.​

Answer 1

x² + 5x + 6 = 0

a = 1     b = 5    c = 6

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-5\pm\sqrt{5^2-4\cdot1\cdot6}}{2\cdot1}=\frac{-5\pm\sqrt{25-24}}{2}=\frac{-5\pm\sqrt{1}}{2}=\frac{-5\pm1}{2}\\\\x'=\frac{-5+1}{2}=\frac{-4}{2}=-2\\\\x''=\frac{-5-1}{2}=\frac{-6}{2}=-3$

S = {-3, -2}