Question

Calcule as raizes -x²+x+12=0

Answer 1

-x²+x+12=0

Δ=b²-4ac
Δ=(1)²-4.(-1).(12)
Δ=1+48
Δ=49

x = (-b ± √Δ)/2a
x = (-(1) ± √49)/2.(-1)
x = (-1 ± 7)/-2

x’= (-1+7)/-2
x’= 6/-2
x’=-3

x”= (-1-7)/-2
x”=-8/-2
x”= 4

Raizes: -3 e 4