Faça as alterações de temperatura:
a) 50° C em °F
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b) 10° C em °F
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c) -5° C em °F
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d) 100° C em °F
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e) -15° C em °F
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f) 80° C em °F
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g) -4° C em °F
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h) 0° C em °F
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i) -20° C em °F
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j) 25° C em °F
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Respostas
Resposta:a) 122°f b) 50°f c) 23°f d)212°f e) 5°f f)176°f g) 24,8°f h)32°f i) -4°f j) 77°f
Explicação:
a)Tc= 5(Tf-32)/9 b) 10=5(Tf-32)/9 c)-5=5(Tf-32)/9 d)100=5(Tf-32)/9
50=5(Tf-32)/9 10/5=(Tf-32)/9 -5/5=(Tf-32)/9 100/5=(Tf-32)/9
50/5=(Tf-32)/9 2x9=Tf-32 -1x9=Tf-32 20x9=Tf-32
10x9=Tf-32 18+32=Tf -9+32=Tf 180+32=Tf
90+32= Tf Tf=50°f Tf=23°f Tf=212°f
Tf=122°f
e)-15=5(Tf-32)/9 f)80=5(Tf-32)/9 g)-4=5(Tf-32)/9 h)0=5(Tf-32)/9
-15/5=(Tf-32)/9 80/5=(Tf-32)/9 -4x9=5(Tf-32) 0/5x9=Tf-32
-3x9=Tf-32 16x9=Tf-32 -36/5=Tf-32 0+32= Tf
-27+32=Tf 144+32=Tf -7,2+32=Tf Tf=32°f
Tf=5 Tf=176°f Tf=24,8°f
i)-20=5(Tf-32)/9 j)25=5(Tf-32)/9
-20x9=5(Tf-32) 25/5=(Tf-32)/9
-180/5=Tf-32 5x9=Tf-32
-36+32=Tf 45+32=Tf
Tf=-4 Tf=77°f
a) 100___180
50___ x-32
100(x -32) = 50×180
100x -3200 = 9000
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